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Suppose the resistance is 47 K and the current is 680 mA. What is the power dissipated by the potentiometer Use the formula P I 2R, after converting to ohms and amperes. Then P 0.680 0.680 47,000 22,000 W 22 kW. This is a ridiculous state of affairs. An ordinary potentiometer, such as the one you would get at an electronics store, dissipating 22 kW, several times more than a typical household. The voltage must be phenomenal. It s not too hard to figure out that such a voltage would burn out the potentiometer so fast that it would be ruined before the little Pow! could even begin to register.

' ' set the mode to 2400 baud, IrDA ' this writes to the configuration register writemode: low cs shiftout din,sclk,msbfirst,[$C08D<\\>16] high cs

Problem 4-13

Just from curiosity, what is the voltage that would cause so much current to be driven through such a large resistance Use Ohm s Law to find the current: E IR 0.680 47, 000 32,000 V 32 kV. That s the sort of voltage you d expect to find only in certain industrial/commercial applications. The resistance capable of drawing 680 mA from such a voltage would surely not be a potentiometer, but perhaps something like an amplifier tube in a radio broadcast transmitter.

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In 2, we examine the 10 principles of finance and lay the groundwork for all that follows. As we describe each principle, we also recommend how you can use it to make better investment decisions. The principles range from common-sense suggestions, such as minimizing transactions costs, to concepts that may be new for nonfinance types, such as understanding and using a pricing model to value a stock. In 3, we provide definitions relating to valuation, describe the stock valuation process, and introduce you to the discounted cash flow (DCF ) valuation method. We discuss the role that all investors played in inflating the high-tech bubble. We describe the different

' ' transmits the message in data space "fox" ' "the quick brown fox... +CRLF sendfox: char.byte1=$80 ' make rts high, red led on ' rts is bit 1, pin is made high when bit is low. ix=0 sendfox1: ' this loop gets fox, null terminated string. read ix,char.byte0 if char.byte0=0 then sendfoxend sendfox2: low cs pulsout sclk,2 ' get one bit tst=dout ' test that transmit buffer is empty

When you place resistances in series, their ohmic values simply add together to get the total resistance. This is easy to see intuitively, and it s quite simple to remember.

high cs if tst=1 then sendfox2 ' loop back until ready low cs ' now send the character shiftout din,sclk,msbfirst,[char<\\>16] high cs ix=ix+1 goto sendfox1 ' look for next char to send sendfoxend: low cs ' now turn off RTS pin ' the TE<\\> bit=1, so no data is transmitted. shiftout din,sclk,msbfirst,[$8600<\\>16] high cs goto terminal ' back to receiving characters ' and testing cts

Problem 4-14

residual value, and the short-term assets to get today s value of the corporation as a whole the corporate or enterprise value. We describe this procedure in greater depth later in this section. Corporate Value Cash Flow Operations Residual Value Short-term Assets

Suppose the following resistances are hooked up in series with each other: 112 , and 680 . What is the total resistance of the series combination (Fig. 4-8) , 470

' ' now enter a loop to receive data and print it on a debug screen ' jumps to sendfox routine when the hardware cts line is low ' by pressing the pushbutton in the above circuit terminal: low din ' sequence to receive data, both 8-bit status and 8-bit data low cs shiftin dout,sclk,msbpre,[char<\\>16] ' 16 bits total high cs if cts then sendfox ' Jump to sendfox is pushbutton down. ' cts bit is high when the pin is low if Rbit=0 then terminal ' skip printing if there is no character ' Rbit is the flag for this. debug char.byte0 ' print the character goto terminal ' receive more bytes

4-8 Three resistors in series (Problem 4-14).

Listing 5-1

Just add the values, getting a total of 112 + 470 + 680 1262 . You might round this off to 1260 . It depends on the tolerances of the components how precise their actual values are to the ones specified by the manufacturer.

The ValuePro 2002 Software shows this calculation at the top of the General Pro Forma Page. Again, this simple spreadsheet program does the work automatically. Step 4: Calculate Intrinsic Stock Value. We subtract the value of the company s short-term liabilities and senior liabilities debt and preferred stock from the enterprise value to get value to common equity, as shown in the following. Value to Common Equity Corporate Value (Debt Preferred)

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